What are the solutions to the equation 2x^3+3x^2-18x=27 ?

The solutions to the equation 2x^3+3x^2-18x=27 are x=-3/2 ,x=-3,x=3

Find the zeros of 2x^3+3x^2-18x=27

The zeros of 2x^3+3x^2-18x=27 are x=-3/2 ,x=-3,x=3

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2 x^{3} + 3 x^{2} - 18 x = 27

x = - \frac{3}{2}, x = - 3, x = 3

Solution steps

2 x^{3} + 3 x^{2} - 18 x = 27

Move

27

to the left side

2 x^{3} + 3 x^{2} - 18 x - 27 = 0

Factor

2 x^{3} + 3 x^{2} - 18 x - 27 : (2 x + 3) (x + 3) (x - 3)

(2 x + 3) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 3 = 0 or x + 3 = 0 or x - 3 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - \frac{3}{2}, x = - 3, x = 3

- 12 x^{4} - 27 x^{3} = 0

14 n^{3} - 2 n^{2} = 0

2 x^{5} - 3 x^{4} - 7 x^{2} + 5 = 0

2 x^{4} + x^{3} - 29 x^{2} - 34 x = 24

400 = t^{3} + 2 t

What are the solutions to the equation 2x^3+3x^2-18x=27 ?
The solutions to the equation 2x^3+3x^2-18x=27 are x=-3/2 ,x=-3,x=3
Find the zeros of 2x^3+3x^2-18x=27
The zeros of 2x^3+3x^2-18x=27 are x=-3/2 ,x=-3,x=3