What are the solutions to the equation 4c^3+24c^2-64c=0 ?

The solutions to the equation 4c^3+24c^2-64c=0 are c=0,c=2,c=-8

Find the zeros of 4c^3+24c^2-64c=0

The zeros of 4c^3+24c^2-64c=0 are c=0,c=2,c=-8

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4 c^{3} + 24 c^{2} - 64 c = 0

c = 0, c = 2, c = - 8

Solution steps

4 c^{3} + 24 c^{2} - 64 c = 0

Factor

4 c^{3} + 24 c^{2} - 64 c : 4 c (c - 2) (c + 8)

4 c (c - 2) (c + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

c = 0 or c - 2 = 0 or c + 8 = 0

Solve

c - 2 = 0 : c = 2

Solve

c + 8 = 0 : c = - 8

The solutions are

c = 0, c = 2, c = - 8

x^{2} - 6 x = 2 x^{2} x

- a^{3} + 6 a^{2} + 15 a + 8 = 0

3 = n^{3} - 3 n^{2} + n

n^{2} + n^{3} = - 180

x^{3} - 27 x - 27 = 0

What are the solutions to the equation 4c^3+24c^2-64c=0 ?
The solutions to the equation 4c^3+24c^2-64c=0 are c=0,c=2,c=-8
Find the zeros of 4c^3+24c^2-64c=0
The zeros of 4c^3+24c^2-64c=0 are c=0,c=2,c=-8