What are the solutions to the equation 0=x^3-2x^2-11x+12 ?

The solutions to the equation 0=x^3-2x^2-11x+12 are x=1,x=-3,x=4

Find the zeros of 0=x^3-2x^2-11x+12

The zeros of 0=x^3-2x^2-11x+12 are x=1,x=-3,x=4

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0 = x^{3} - 2 x^{2} - 11 x + 12

x = 1, x = - 3, x = 4

Solution steps

0 = x^{3} - 2 x^{2} - 11 x + 12

Switch sides

x^{3} - 2 x^{2} - 11 x + 12 = 0

Factor

x^{3} - 2 x^{2} - 11 x + 12 : (x - 1) (x + 3) (x - 4)

(x - 1) (x + 3) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 3 = 0 or x - 4 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 3 = 0 : x = - 3

Solve

x - 4 = 0 : x = 4

The solutions are

x = 1, x = - 3, x = 4

a \cdot a \cdot a = 3 a

2 x^{3} + 3 x^{2} - 17 x + 12 = 0

z^{4} - 49 = 0

0.000004 x^{3} - 400 = 0

2 x (64 x^{2}) - 8 x^{2} (8 x) = 1

What are the solutions to the equation 0=x^3-2x^2-11x+12 ?
The solutions to the equation 0=x^3-2x^2-11x+12 are x=1,x=-3,x=4
Find the zeros of 0=x^3-2x^2-11x+12
The zeros of 0=x^3-2x^2-11x+12 are x=1,x=-3,x=4