What are the solutions to the equation x^4+8x^3+9x^2-28x+10=0 ?

The solutions to the equation x^4+8x^3+9x^2-28x+10=0 are x=1,x=-5,x=-2+sqrt(6),x=-2-sqrt(6)

Find the zeros of x^4+8x^3+9x^2-28x+10=0

The zeros of x^4+8x^3+9x^2-28x+10=0 are x=1,x=-5,x=-2+sqrt(6),x=-2-sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{4} + 8 x^{3} + 9 x^{2} - 28 x + 10 = 0

x = 1, x = - 5, x = - 2 + 6, x = - 2 - 6

Solution steps

x^{4} + 8 x^{3} + 9 x^{2} - 28 x + 10 = 0

Factor

x^{4} + 8 x^{3} + 9 x^{2} - 28 x + 10 : (x - 1) (x + 5) (x^{2} + 4 x - 2)

(x - 1) (x + 5) (x^{2} + 4 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 5 = 0 or x^{2} + 4 x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 5 = 0 : x = - 5

Solve

x^{2} + 4 x - 2 = 0 : x = - 2 + 6, x = - 2 - 6

The solutions are

x = 1, x = - 5, x = - 2 + 6, x = - 2 - 6

x^{50} = 0.01

x^{3} - 3 x^{2} - 44 x + 2222 = 5.88

0.0012 = x^{3}

x^{4} + 2 x^{3} - 6 x^{2} + 3 x = 0

x^{4} + 9 x^{3} + 18 x^{2} = 0

What are the solutions to the equation x^4+8x^3+9x^2-28x+10=0 ?
The solutions to the equation x^4+8x^3+9x^2-28x+10=0 are x=1,x=-5,x=-2+sqrt(6),x=-2-sqrt(6)
Find the zeros of x^4+8x^3+9x^2-28x+10=0
The zeros of x^4+8x^3+9x^2-28x+10=0 are x=1,x=-5,x=-2+sqrt(6),x=-2-sqrt(6)