What are the solutions to the equation 6804=3780(1+r)^4 ?

The solutions to the equation 6804=3780(1+r)^4 are r=\sqrt[4]{9/5}-1,r=-\sqrt[4]{9/5}-1

Find the zeros of 6804=3780(1+r)^4

The zeros of 6804=3780(1+r)^4 are r=\sqrt[4]{9/5}-1,r=-\sqrt[4]{9/5}-1

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6804 = 3780 (1 + r)^{4}

Decimal Notation

r = 0.15829 \dots, r = - 2.15829 \dots

Solution steps

6804 = 3780 (1 + r)^{4}

Switch sides

3780 (1 + r)^{4} = 6804

Divide both sides by

3780

(1 + r)^{4} = \frac{9}{5}

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

7 + 10 + 63 - 40 + 89 - 88 + 101 - 140 = x^{5}

x^{3} = 35 (3) + 20

2 x^{4} + 5 x^{2} - 3 = 0

3^{2} + y^{3} = 16 y + 1

b^{4} + 9 b^{2} + 18 = 0

What are the solutions to the equation 6804=3780(1+r)^4 ?
The solutions to the equation 6804=3780(1+r)^4 are r=\sqrt[4]{9/5}-1,r=-\sqrt[4]{9/5}-1
Find the zeros of 6804=3780(1+r)^4
The zeros of 6804=3780(1+r)^4 are r=\sqrt[4]{9/5}-1,r=-\sqrt[4]{9/5}-1