What are the solutions to the equation r^2-25=0 ?

The solutions to the equation r^2-25=0 are r=5,r=-5

Find the zeros of r^2-25=0

The zeros of r^2-25=0 are r=5,r=-5

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r^{2} - 25 = 0

r = 5, r = - 5

Solution steps

r^{2} - 25 = 0

Move

25

to the right side

r^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = 25, r = - 25

25 = 5

- 25 = - 5

r = 5, r = - 5

\frac{v}{2} + 9 = 28

(\frac{3}{4}) x + (\frac{2}{5}) = (\frac{1}{2}) x - (\frac{1}{10})

\frac{3}{280} + \frac{1}{150} + \frac{11}{225}

\frac{1}{0.00001}

∣ x - 13 ∣ < 4

What are the solutions to the equation r^2-25=0 ?
The solutions to the equation r^2-25=0 are r=5,r=-5
Find the zeros of r^2-25=0
The zeros of r^2-25=0 are r=5,r=-5