What are the solutions to the equation -x^3+24x^2-180x+432=0 ?

The solutions to the equation -x^3+24x^2-180x+432=0 are x=6,x=12

Find the zeros of -x^3+24x^2-180x+432=0

The zeros of -x^3+24x^2-180x+432=0 are x=6,x=12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{3} + 24 x^{2} - 180 x + 432 = 0

x = 6, x = 12

Solution steps

- x^{3} + 24 x^{2} - 180 x + 432 = 0

Factor

- x^{3} + 24 x^{2} - 180 x + 432 : - (x - 6)^{2} (x - 12)

- (x - 6)^{2} (x - 12) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 6 = 0 or x - 12 = 0

Solve

x - 6 = 0 : x = 6

Solve

x - 12 = 0 : x = 12

The solutions are

x = 6, x = 12

x^{3} - x^{2} + x + 4 = 3 x^{2} - 2 x + 4

x^{4} x + 8 = 8 x + 16

2 x^{5} - 12 x^{3} = - 16 x

- λ^{3} - 13 λ^{2} - 56 λ - 80 = 0

x^{3} + 2 x^{2} = x + 2

What are the solutions to the equation -x^3+24x^2-180x+432=0 ?
The solutions to the equation -x^3+24x^2-180x+432=0 are x=6,x=12
Find the zeros of -x^3+24x^2-180x+432=0
The zeros of -x^3+24x^2-180x+432=0 are x=6,x=12