What are the solutions to the equation -X^3+9X^2-24X+20=0 ?

The solutions to the equation -X^3+9X^2-24X+20=0 are X=2,X=5

Find the zeros of -X^3+9X^2-24X+20=0

The zeros of -X^3+9X^2-24X+20=0 are X=2,X=5

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- X^{3} + 9 X^{2} - 24 X + 20 = 0

X = 2, X = 5

Solution steps

- X^{3} + 9 X^{2} - 24 X + 20 = 0

Factor

- X^{3} + 9 X^{2} - 24 X + 20 : - (X - 2)^{2} (X - 5)

- (X - 2)^{2} (X - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

X - 2 = 0 or X - 5 = 0

Solve

X - 2 = 0 : X = 2

Solve

X - 5 = 0 : X = 5

The solutions are

X = 2, X = 5

x^{3} + x^{2} = 6 x

(5 x - 2)^{3} - (5 x - 2) = 0

(x + 1)^{3} + x + 1 = 0

x^{3} + 25.3 x^{2} + 219.5 x + 660.1 = 0

x^{5} - 50 = 0

What are the solutions to the equation -X^3+9X^2-24X+20=0 ?
The solutions to the equation -X^3+9X^2-24X+20=0 are X=2,X=5
Find the zeros of -X^3+9X^2-24X+20=0
The zeros of -X^3+9X^2-24X+20=0 are X=2,X=5