What are the solutions to the equation 4x^3-26x=0 ?

The solutions to the equation 4x^3-26x=0 are x=0,x=-sqrt(13/2),x=sqrt(13/2)

Find the zeros of 4x^3-26x=0

The zeros of 4x^3-26x=0 are x=0,x=-sqrt(13/2),x=sqrt(13/2)

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4 x^{3} - 26 x = 0

x = 0, x = - \frac{13}{2}, x = \frac{13}{2}

Decimal Notation

x = 0, x = - 2.54950 \dots, x = 2.54950 \dots

Solution steps

4 x^{3} - 26 x = 0

Factor

4 x^{3} - 26 x : 2 x (2 x + 13) (2 x - 13)

2 x (2 x + 13) (2 x - 13) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 13 = 0 or 2 x - 13 = 0

Solve

2 x + 13 = 0 : x = - \frac{13}{2}

Solve

2 x - 13 = 0 : x = \frac{13}{2}

The solutions are

x = 0, x = - \frac{13}{2}, x = \frac{13}{2}

x^{4} - 6 x^{3} + 11 x^{2} - 6 x = 0

x^{4} + x^{3} - 6 x^{2} = 0

- x^{4} + x^{2} + 12 = 0

x^{4} - 1 7^{2} + 16 = 0

0 = x^{6} - 7 x^{4} - 8 x^{2}

What are the solutions to the equation 4x^3-26x=0 ?
The solutions to the equation 4x^3-26x=0 are x=0,x=-sqrt(13/2),x=sqrt(13/2)
Find the zeros of 4x^3-26x=0
The zeros of 4x^3-26x=0 are x=0,x=-sqrt(13/2),x=sqrt(13/2)