What are the solutions to the equation 0=4x^3-9x^2+6x-1 ?

The solutions to the equation 0=4x^3-9x^2+6x-1 are x=1,x= 1/4

Find the zeros of 0=4x^3-9x^2+6x-1

The zeros of 0=4x^3-9x^2+6x-1 are x=1,x= 1/4

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0 = 4 x^{3} - 9 x^{2} + 6 x - 1

x = 1, x = \frac{1}{4}

Decimal Notation

x = 1, x = 0.25

Solution steps

0 = 4 x^{3} - 9 x^{2} + 6 x - 1

Switch sides

4 x^{3} - 9 x^{2} + 6 x - 1 = 0

Factor

4 x^{3} - 9 x^{2} + 6 x - 1 : (x - 1)^{2} (4 x - 1)

(x - 1)^{2} (4 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 4 x - 1 = 0

Solve

x - 1 = 0 : x = 1

Solve

4 x - 1 = 0 : x = \frac{1}{4}

The solutions are

x = 1, x = \frac{1}{4}

x^{4} - 3 x^{2} + 2 x - 5 = 0

0 = x^{3} - 2 x + 1

- x^{4} + x^{3} + 45 x^{2} - 25 x - 500 = 0

x = \frac{2}{3} π r^{3}, r

49 y^{3} - 16 y = 0

What are the solutions to the equation 0=4x^3-9x^2+6x-1 ?
The solutions to the equation 0=4x^3-9x^2+6x-1 are x=1,x= 1/4
Find the zeros of 0=4x^3-9x^2+6x-1
The zeros of 0=4x^3-9x^2+6x-1 are x=1,x= 1/4