What are the solutions to the equation (1+x)^{12}=1.12 ?

The solutions to the equation (1+x)^{12}=1.12 are x=0.00948…,x=-2.00948…

Find the zeros of (1+x)^{12}=1.12

The zeros of (1+x)^{12}=1.12 are x=0.00948…,x=-2.00948…

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(1 + x)^{12} = 1.12

x = 0.00948 \dots, x = - 2.00948 \dots

Solution steps

(1 + x)^{12} = 1.12

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = 0.00948 \dots, x = - 2.00948 \dots

(1 + x)^{12} = 1.15

- x^{3} - 36 x^{2} - 416 x - 1552 = 0

x^{3} - x^{2} - x + 5 = 0

(- 2) = x^{3} - 2 x^{2} + 2

x^{3} - 3 x^{2} - 9 x + 4 = 0

What are the solutions to the equation (1+x)^{12}=1.12 ?
The solutions to the equation (1+x)^{12}=1.12 are x=0.00948…,x=-2.00948…
Find the zeros of (1+x)^{12}=1.12
The zeros of (1+x)^{12}=1.12 are x=0.00948…,x=-2.00948…