What are the solutions to the equation 2x(x^3-216)=0 ?

The solutions to the equation 2x(x^3-216)=0 are x=0,x=6,x=-3+3sqrt(3)i,x=-3-3sqrt(3)i

Find the zeros of 2x(x^3-216)=0

The zeros of 2x(x^3-216)=0 are x=0,x=6,x=-3+3sqrt(3)i,x=-3-3sqrt(3)i

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2 x (x^{3} - 216) = 0

x = 0, x = 6, x = - 3 + 33 i, x = - 3 - 33 i

Solution steps

2 x (x^{3} - 216) = 0

Factor

2 x (x^{3} - 216) : 2 x (x - 6) (x^{2} + 6 x + 36)

2 x (x - 6) (x^{2} + 6 x + 36) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 6 = 0 or x^{2} + 6 x + 36 = 0

Solve

x - 6 = 0 : x = 6

Solve

x^{2} + 6 x + 36 = 0 : x = - 3 + 33 i, x = - 3 - 33 i

The solutions are

x = 0, x = 6, x = - 3 + 33 i, x = - 3 - 33 i

x^{4} + 2 x^{3} - 14 x^{2} + 2 x + 1 = 0

0.5 (5 - 7 x) = 8 - (4 x^{6})

x, x^{4} + y^{4} = 2

125000 (x)^{6} = 165000

x^{4} + x^{3} + 4 x^{2} + x + 3 = 0

What are the solutions to the equation 2x(x^3-216)=0 ?
The solutions to the equation 2x(x^3-216)=0 are x=0,x=6,x=-3+3sqrt(3)i,x=-3-3sqrt(3)i
Find the zeros of 2x(x^3-216)=0
The zeros of 2x(x^3-216)=0 are x=0,x=6,x=-3+3sqrt(3)i,x=-3-3sqrt(3)i