What are the solutions to the equation x^2+x+4=0 ?

The solutions to the equation x^2+x+4=0 are x=-1/2+i(sqrt(15))/2 ,x=-1/2-i(sqrt(15))/2

Find the zeros of x^2+x+4=0

The zeros of x^2+x+4=0 are x=-1/2+i(sqrt(15))/2 ,x=-1/2-i(sqrt(15))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + x + 4 = 0

x = - \frac{1}{2} + i \frac{15}{2}, x = - \frac{1}{2} - i \frac{15}{2}

Solution steps

x^{2} + x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 4 : 15 i

x_{1, 2} = \frac{- 1 \pm 15 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 15 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 15 i}{2 \cdot 1}

x = \frac{- 1 + 15 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{15}{2}

x = \frac{- 1 - 15 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{15}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{15}{2}, x = - \frac{1}{2} - i \frac{15}{2}

\frac{10}{3} x - x^{2} - 1 = 0

i^{- 8}

(m + 5) (3 m + 4) = 3 (m + 2) - 2

- 9 a - 1 < 26

(\frac{3}{4})^{- 1} - (\frac{1}{2})^{0}

What are the solutions to the equation x^2+x+4=0 ?
The solutions to the equation x^2+x+4=0 are x=-1/2+i(sqrt(15))/2 ,x=-1/2-i(sqrt(15))/2
Find the zeros of x^2+x+4=0
The zeros of x^2+x+4=0 are x=-1/2+i(sqrt(15))/2 ,x=-1/2-i(sqrt(15))/2