What are the solutions to the equation -y^3+y^2-5y=24 ?

The solutions to the equation -y^3+y^2-5y=24 are y\approx-2.09235…

Find the zeros of -y^3+y^2-5y=24

The zeros of -y^3+y^2-5y=24 are y\approx-2.09235…

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- y^{3} + y^{2} - 5 y = 24

y \approx - 2.09235 \dots

Solution steps

- y^{3} + y^{2} - 5 y = 24

Move

24

to the left side

- y^{3} + y^{2} - 5 y - 24 = 0

Find one solution for

- y^{3} + y^{2} - 5 y - 24 = 0

using Newton-Raphson:

y \approx - 2.09235 \dots

Apply long division:

\frac{- y ^{3} + y ^{2} - 5 y - 24}{y + 2.09235 \dots} = - y^{2} + 3.09235 \dots y - 11.47031 \dots

- y^{2} + 3.09235 \dots y - 11.47031 \dots \approx 0

Find one solution for

- y^{2} + 3.09235 \dots y - 11.47031 \dots = 0

using Newton-Raphson:

No Solution for

y \in R

The solution is

y \approx - 2.09235 \dots

z^{4} - z^{3} + z^{2} - z + 1 = 0

x^{4} - 41 x^{2} + 300 = 0

2 x^{3} = 250

64 - 729 x^{3} = 0

x^{3} - 4 x^{2} - 3 x + 10 = 0

What are the solutions to the equation -y^3+y^2-5y=24 ?
The solutions to the equation -y^3+y^2-5y=24 are y\approx-2.09235…
Find the zeros of -y^3+y^2-5y=24
The zeros of -y^3+y^2-5y=24 are y\approx-2.09235…