What are the solutions to the equation x^3+12x^2=-35x ?

The solutions to the equation x^3+12x^2=-35x are x=0,x=-5,x=-7

Find the zeros of x^3+12x^2=-35x

The zeros of x^3+12x^2=-35x are x=0,x=-5,x=-7

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x^{3} + 12 x^{2} = - 35 x

x = 0, x = - 5, x = - 7

Solution steps

x^{3} + 12 x^{2} = - 35 x

Move

35 x

to the left side

x^{3} + 12 x^{2} + 35 x = 0

Factor

x^{3} + 12 x^{2} + 35 x : x (x + 5) (x + 7)

x (x + 5) (x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 5 = 0 or x + 7 = 0

Solve

x + 5 = 0 : x = - 5

Solve

x + 7 = 0 : x = - 7

The solutions are

x = 0, x = - 5, x = - 7

t^{3} - t = 0

51 = 45 + z^{11}

- 11 x^{3} - 18 = 8

- x^{3} + 12 x^{2} - 45 x + 54 = 0

2 x^{5} - 5 x + 2 = 0

What are the solutions to the equation x^3+12x^2=-35x ?
The solutions to the equation x^3+12x^2=-35x are x=0,x=-5,x=-7
Find the zeros of x^3+12x^2=-35x
The zeros of x^3+12x^2=-35x are x=0,x=-5,x=-7