What are the solutions to the equation (5xa)(bx^2)=35x^8 ?

The solutions to the equation (5xa)(bx^2)=35x^8 are x=0,x=\sqrt[5]{(ab)/7}

Find the zeros of (5xa)(bx^2)=35x^8

The zeros of (5xa)(bx^2)=35x^8 are x=0,x=\sqrt[5]{(ab)/7}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(5 x a) (b x^{2}) = 35 x^{8}

Solution steps

(5 x a) (b x^{2}) = 35 x^{8}

Move

35 x^{8}

to the left side

5 x ab x^{2} - 35 x^{8} = 0

Factor

5 x ab x^{2} - 35 x^{8} : 5 x^{3} (ab - 7 x^{5})

5 x^{3} (ab - 7 x^{5}) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or ab - 7 x^{5} = 0

Solve

The solutions are

(x - 2)^{5} = 11

0 = θ^{1} + θ^{2} + θ^{3}

x^{3} - 7 x^{2} + 5 x + 2 = 0

2 x^{3} + x^{2} - 1 = 1

x^{3} - 3 x^{2} - 9 x + 5 = 0

What are the solutions to the equation (5xa)(bx^2)=35x^8 ?
The solutions to the equation (5xa)(bx^2)=35x^8 are x=0,x=\sqrt[5]{(ab)/7}
Find the zeros of (5xa)(bx^2)=35x^8
The zeros of (5xa)(bx^2)=35x^8 are x=0,x=\sqrt[5]{(ab)/7}