What are the solutions to the equation (x-5)(x^2+x+1)=0 ?

The solutions to the equation (x-5)(x^2+x+1)=0 are x=5,x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2

Find the zeros of (x-5)(x^2+x+1)=0

The zeros of (x-5)(x^2+x+1)=0 are x=5,x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 5) (x^{2} + x + 1) = 0

x = 5, x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

Solution steps

(x - 5) (x^{2} + x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x^{2} + x + 1 = 0

Solve

x - 5 = 0 : x = 5

Solve

x^{2} + x + 1 = 0 : x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

The solutions are

x = 5, x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

x^{3} + 11 x^{2} + 23 x - 35 = 0

y, x = (y - 2)^{3}

z^{3} = 4 + 4 i 3

9 x^{4} = 12 x^{2} - 4

(5 - 2 x)^{3} = - 1

What are the solutions to the equation (x-5)(x^2+x+1)=0 ?
The solutions to the equation (x-5)(x^2+x+1)=0 are x=5,x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2
Find the zeros of (x-5)(x^2+x+1)=0
The zeros of (x-5)(x^2+x+1)=0 are x=5,x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2