What are the solutions to the equation x^3-12x^2+49x-58=0 ?

The solutions to the equation x^3-12x^2+49x-58=0 are x=2,x=5+2i,x=5-2i

Find the zeros of x^3-12x^2+49x-58=0

The zeros of x^3-12x^2+49x-58=0 are x=2,x=5+2i,x=5-2i

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x^{3} - 12 x^{2} + 49 x - 58 = 0

x = 2, x = 5 + 2 i, x = 5 - 2 i

Solution steps

x^{3} - 12 x^{2} + 49 x - 58 = 0

Factor

x^{3} - 12 x^{2} + 49 x - 58 : (x - 2) (x^{2} - 10 x + 29)

(x - 2) (x^{2} - 10 x + 29) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} - 10 x + 29 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} - 10 x + 29 = 0 : x = 5 + 2 i, x = 5 - 2 i

The solutions are

x = 2, x = 5 + 2 i, x = 5 - 2 i

8 = b^{3}

20 x^{3} - 90 x = 0

48.46 x^{3} - 12.6 x + 0.005 = 0

x, x^{5} + x^{3} + x = 3

2 x^{4} - 11 x^{2} + 12 = 0

What are the solutions to the equation x^3-12x^2+49x-58=0 ?
The solutions to the equation x^3-12x^2+49x-58=0 are x=2,x=5+2i,x=5-2i
Find the zeros of x^3-12x^2+49x-58=0
The zeros of x^3-12x^2+49x-58=0 are x=2,x=5+2i,x=5-2i