What are the solutions to the equation z^4=3+2i ?

The solutions to the equation z^4=3+2i are

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z^4=3+2i

z^{4} = 3 + 2 i

Solution steps

z^{4} = 3 + 2 i

For

z^{n} = a

the solutions are

k = 0, 1, \dots, n - 1

For

n = 4, a = 3 + 2 i

∣ a ∣ = 13

ar g (a) = arctan (\frac{2}{3})

Simplify

x^{4} + 6 x^{3} + 18 x^{2} + 22 x + 17 = 0

0 = x^{3} + 8

x^{4} - 12 x^{3} + 48 x^{2} - 73 x + 36 = 0

(\frac{x - 3}{2})^{3} - 1 = 8

0 = x^{3} - 4

What are the solutions to the equation z^4=3+2i ?
The solutions to the equation z^4=3+2i are
Find the zeros of z^4=3+2i
The zeros of z^4=3+2i are