What are the solutions to the equation x^3-3x^2-16x=-48 ?

The solutions to the equation x^3-3x^2-16x=-48 are x=3,x=-4,x=4

Find the zeros of x^3-3x^2-16x=-48

The zeros of x^3-3x^2-16x=-48 are x=3,x=-4,x=4

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x^{3} - 3 x^{2} - 16 x = - 48

x = 3, x = - 4, x = 4

Solution steps

x^{3} - 3 x^{2} - 16 x = - 48

Move

48

to the left side

x^{3} - 3 x^{2} - 16 x + 48 = 0

Factor

x^{3} - 3 x^{2} - 16 x + 48 : (x - 3) (x + 4) (x - 4)

(x - 3) (x + 4) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 4 = 0 or x - 4 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 4 = 0 : x = - 4

Solve

x - 4 = 0 : x = 4

The solutions are

x = 3, x = - 4, x = 4

(1 + \frac{x}{12})^{12} = 1.12

59663.11 = 200000 (1 + x)^{5}

x^{4} - 8 x^{3} + 24 x^{2} - 32 x + 17 = 0

5 x^{4} + 40 x^{3} + 75 x^{2} = 0

x^{3} - 2.6 x^{2} - x + 1.6 = 0

What are the solutions to the equation x^3-3x^2-16x=-48 ?
The solutions to the equation x^3-3x^2-16x=-48 are x=3,x=-4,x=4
Find the zeros of x^3-3x^2-16x=-48
The zeros of x^3-3x^2-16x=-48 are x=3,x=-4,x=4