What are the solutions to the equation 3(x^2-1)(x^2+100)=0 ?

The solutions to the equation 3(x^2-1)(x^2+100)=0 are x=-1,x=1,x=10i,x=-10i

Find the zeros of 3(x^2-1)(x^2+100)=0

The zeros of 3(x^2-1)(x^2+100)=0 are x=-1,x=1,x=10i,x=-10i

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3 (x^{2} - 1) (x^{2} + 100) = 0

x = - 1, x = 1, x = 10 i, x = - 10 i

Solution steps

3 (x^{2} - 1) (x^{2} + 100) = 0

Factor

3 (x^{2} - 1) (x^{2} + 100) : 3 (x + 1) (x - 1) (x^{2} + 100)

3 (x + 1) (x - 1) (x^{2} + 100) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 1 = 0 or x^{2} + 100 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

Solve

x^{2} + 100 = 0 : x = 10 i, x = - 10 i

The solutions are

x = - 1, x = 1, x = 10 i, x = - 10 i

6 x^{5} - 12 x^{3} + 6 x = 0

4 x^{3} - 44 x^{2} + 120 x = 50

(x) = (1 + 3 x) (x - x^{2})

y^{4} - 13 y + 36 = 0

100 (1 + x)^{10} = 50 (1 + x)^{16}

What are the solutions to the equation 3(x^2-1)(x^2+100)=0 ?
The solutions to the equation 3(x^2-1)(x^2+100)=0 are x=-1,x=1,x=10i,x=-10i
Find the zeros of 3(x^2-1)(x^2+100)=0
The zeros of 3(x^2-1)(x^2+100)=0 are x=-1,x=1,x=10i,x=-10i