What are the solutions to the equation ((1+r)/(12))^{12}=e^p ?

The solutions to the equation ((1+r)/(12))^{12}=e^p are r=12\sqrt[12]{e^p}-1,r=-12\sqrt[12]{e^p}-1

Find the zeros of ((1+r)/(12))^{12}=e^p

The zeros of ((1+r)/(12))^{12}=e^p are r=12\sqrt[12]{e^p}-1,r=-12\sqrt[12]{e^p}-1

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(\frac{1 + r}{12})^{12} = e^{p}

Solution steps

(\frac{1 + r}{12})^{12} = e^{p}

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x^{3} + x^{2} + x + 10 = 0

x^{3} - 18 x^{2} = 0

2 x^{4} - 32 x^{2} + 120 = 0

- λ^{3} + 3 λ^{2} - 3 λ + 1 = 0

x^{4} - 52 x^{2} + 576 = 0

What are the solutions to the equation ((1+r)/(12))^{12}=e^p ?
The solutions to the equation ((1+r)/(12))^{12}=e^p are r=12\sqrt[12]{e^p}-1,r=-12\sqrt[12]{e^p}-1
Find the zeros of ((1+r)/(12))^{12}=e^p
The zeros of ((1+r)/(12))^{12}=e^p are r=12\sqrt[12]{e^p}-1,r=-12\sqrt[12]{e^p}-1