What are the solutions to the equation x(2x-5)(3x+9)=0 ?

The solutions to the equation x(2x-5)(3x+9)=0 are x=0,x= 5/2 ,x=-3

Find the zeros of x(2x-5)(3x+9)=0

The zeros of x(2x-5)(3x+9)=0 are x=0,x= 5/2 ,x=-3

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x (2 x - 5) (3 x + 9) = 0

x = 0, x = \frac{5}{2}, x = - 3

Decimal Notation

x = 0, x = 2.5, x = - 3

Solution steps

x (2 x - 5) (3 x + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x - 5 = 0 or 3 x + 9 = 0

Solve

2 x - 5 = 0 : x = \frac{5}{2}

Solve

3 x + 9 = 0 : x = - 3

The solutions are

x = 0, x = \frac{5}{2}, x = - 3

x^{4} - 2 x^{3} + 3 x^{2} - 6 x = 0

x^{1} = 8 \cdot x^{3}

2 x^{3} - 6 x^{2} - 80 x = 0

0 = 2 x^{3} - 8 x

8 = y^{3}

What are the solutions to the equation x(2x-5)(3x+9)=0 ?
The solutions to the equation x(2x-5)(3x+9)=0 are x=0,x= 5/2 ,x=-3
Find the zeros of x(2x-5)(3x+9)=0
The zeros of x(2x-5)(3x+9)=0 are x=0,x= 5/2 ,x=-3