What are the solutions to the equation 10(4x^3-15x^2+16x-4)=0 ?

The solutions to the equation 10(4x^3-15x^2+16x-4)=0 are x=2,x=(7+sqrt(17))/8 ,x=(7-sqrt(17))/8

Find the zeros of 10(4x^3-15x^2+16x-4)=0

The zeros of 10(4x^3-15x^2+16x-4)=0 are x=2,x=(7+sqrt(17))/8 ,x=(7-sqrt(17))/8

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10 (4 x^{3} - 15 x^{2} + 16 x - 4) = 0

x = 2, x = \frac{7 + 17}{8}, x = \frac{7 - 17}{8}

Decimal Notation

x = 2, x = 1.39038 \dots, x = 0.35961 \dots

Solution steps

10 (4 x^{3} - 15 x^{2} + 16 x - 4) = 0

Factor

10 (4 x^{3} - 15 x^{2} + 16 x - 4) : 10 (x - 2) (4 x^{2} - 7 x + 2)

10 (x - 2) (4 x^{2} - 7 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 4 x^{2} - 7 x + 2 = 0

Solve

x - 2 = 0 : x = 2

Solve

4 x^{2} - 7 x + 2 = 0 : x = \frac{7 + 17}{8}, x = \frac{7 - 17}{8}

The solutions are

x = 2, x = \frac{7 + 17}{8}, x = \frac{7 - 17}{8}

k^{3} - 3 k^{2} + k + 2 = 0

5 = 3 x^{3} + 4 x^{2} + 6 x + 5

(2 x - 1)^{6} = (2 x - 1)^{8}

C^{8} = \frac{ln ( 7 ) + C}{7}

4 x^{4} + 11 x^{2} - 3 = 0

What are the solutions to the equation 10(4x^3-15x^2+16x-4)=0 ?
The solutions to the equation 10(4x^3-15x^2+16x-4)=0 are x=2,x=(7+sqrt(17))/8 ,x=(7-sqrt(17))/8
Find the zeros of 10(4x^3-15x^2+16x-4)=0
The zeros of 10(4x^3-15x^2+16x-4)=0 are x=2,x=(7+sqrt(17))/8 ,x=(7-sqrt(17))/8