What are the solutions to the equation -y(1+y^2)=0 ?

The solutions to the equation -y(1+y^2)=0 are y=0,y=i,y=-i

Find the zeros of -y(1+y^2)=0

The zeros of -y(1+y^2)=0 are y=0,y=i,y=-i

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- y (1 + y^{2}) = 0

y = 0, y = i, y = - i

Solution steps

- y (1 + y^{2}) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 1 + y^{2} = 0

Solve

1 + y^{2} = 0 : y = i, y = - i

The solutions are

y = 0, y = i, y = - i

(2 x + 3) (x + 2)^{2} = 4 (2 x + 3)

- x^{3} + 3 x^{2} + 62 x - 184 = 0

x^{3} - 2 x^{2} + 8 - 4 x = 0

1 x^{3} = 2 (1) + 3

4 x^{3} = 2

What are the solutions to the equation -y(1+y^2)=0 ?
The solutions to the equation -y(1+y^2)=0 are y=0,y=i,y=-i
Find the zeros of -y(1+y^2)=0
The zeros of -y(1+y^2)=0 are y=0,y=i,y=-i