What are the solutions to the equation 12b^5-b^4=0 ?

The solutions to the equation 12b^5-b^4=0 are b=0,b= 1/12

Find the zeros of 12b^5-b^4=0

The zeros of 12b^5-b^4=0 are b=0,b= 1/12

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12 b^{5} - b^{4} = 0

b = 0, b = \frac{1}{12}

Decimal Notation

b = 0, b = 0.08333 \dots

Solution steps

12 b^{5} - b^{4} = 0

Factor

12 b^{5} - b^{4} : b^{4} (12 b - 1)

b^{4} (12 b - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

b = 0 or 12 b - 1 = 0

Solve

12 b - 1 = 0 : b = \frac{1}{12}

The solutions are

b = 0, b = \frac{1}{12}

x^{4} + x^{3} + 7 x^{2} + 9 x = 0

x^{4} - 3 x^{3} + 2 x^{2} - 7 x - 11 = 0

(4 x)^{4} (0.5) = 0.0225

x^{4} - 2 x^{2} - 2 x^{2} = 0

13 x^{7} - x = x^{4} - 314

What are the solutions to the equation 12b^5-b^4=0 ?
The solutions to the equation 12b^5-b^4=0 are b=0,b= 1/12
Find the zeros of 12b^5-b^4=0
The zeros of 12b^5-b^4=0 are b=0,b= 1/12