What are the solutions to the equation x^2(2x+1)=0 ?

The solutions to the equation x^2(2x+1)=0 are x=0,x=-1/2

Find the zeros of x^2(2x+1)=0

The zeros of x^2(2x+1)=0 are x=0,x=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} (2 x + 1) = 0

x = 0, x = - \frac{1}{2}

Decimal Notation

x = 0, x = - 0.5

Solution steps

x^{2} (2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 1 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions are

x = 0, x = - \frac{1}{2}

x, x^{6} - 16 x^{4} = 0

(x + 1) (x - 3) (x - 2) = 0

2 x^{3} = 6 x^{2}

r^{4} - 13 r^{2} + 36 = 0

x^{3} + 9 x^{2} + 5 x - 14 = 0

What are the solutions to the equation x^2(2x+1)=0 ?
The solutions to the equation x^2(2x+1)=0 are x=0,x=-1/2
Find the zeros of x^2(2x+1)=0
The zeros of x^2(2x+1)=0 are x=0,x=-1/2