What are the solutions to the equation 3x^3-19x^2+36x-10=0 ?

The solutions to the equation 3x^3-19x^2+36x-10=0 are x= 1/3 ,x=3+i,x=3-i

Find the zeros of 3x^3-19x^2+36x-10=0

The zeros of 3x^3-19x^2+36x-10=0 are x= 1/3 ,x=3+i,x=3-i

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3 x^{3} - 19 x^{2} + 36 x - 10 = 0

x = \frac{1}{3}, x = 3 + i, x = 3 - i

Solution steps

3 x^{3} - 19 x^{2} + 36 x - 10 = 0

Factor

3 x^{3} - 19 x^{2} + 36 x - 10 : (3 x - 1) (x^{2} - 6 x + 10)

(3 x - 1) (x^{2} - 6 x + 10) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 1 = 0 or x^{2} - 6 x + 10 = 0

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

x^{2} - 6 x + 10 = 0 : x = 3 + i, x = 3 - i

The solutions are

x = \frac{1}{3}, x = 3 + i, x = 3 - i

x^{5} + 2 x^{4} + 6 x^{2} + 1 = 114514

x^{3} \cdot 19.5 = 26

x^{3} - 8 = 19

- x^{4} + 4 x^{2} - 3 = 0

z^{5} = - 163 + 16

What are the solutions to the equation 3x^3-19x^2+36x-10=0 ?
The solutions to the equation 3x^3-19x^2+36x-10=0 are x= 1/3 ,x=3+i,x=3-i
Find the zeros of 3x^3-19x^2+36x-10=0
The zeros of 3x^3-19x^2+36x-10=0 are x= 1/3 ,x=3+i,x=3-i