What are the solutions to the equation x^2-5x-56=-2x-2 ?

The solutions to the equation x^2-5x-56=-2x-2 are x=9,x=-6

Find the zeros of x^2-5x-56=-2x-2

The zeros of x^2-5x-56=-2x-2 are x=9,x=-6

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x^{2} - 5 x - 56 = - 2 x - 2

x = 9, x = - 6

Solution steps

x^{2} - 5 x - 56 = - 2 x - 2

Move

2

to the left side

x^{2} - 5 x - 54 = - 2 x

Move

2 x

to the left side

x^{2} - 3 x - 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 54 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 54) = 15

x_{1, 2} = \frac{- ( - 3 ) \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 15}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 15}{2 \cdot 1}

x = \frac{- ( - 3 ) + 15}{2 \cdot 1} : 9

x = \frac{- ( - 3 ) - 15}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 9, x = - 6

3 x^{3} + 15 x^{2} + 18 x

\frac{1}{9} \cdot \frac{3}{8}

x^{2} = 10 x + 3

3 x^{3} + x^{2} + x - 2

3 (x - 1) + 7 = 4 x + 2 - 3 (2 - x)

What are the solutions to the equation x^2-5x-56=-2x-2 ?
The solutions to the equation x^2-5x-56=-2x-2 are x=9,x=-6
Find the zeros of x^2-5x-56=-2x-2
The zeros of x^2-5x-56=-2x-2 are x=9,x=-6