What are the solutions to the equation (x^2+7x+49)(x-7)=218 ?

The solutions to the equation (x^2+7x+49)(x-7)=218 are

Find the zeros of (x^2+7x+49)(x-7)=218

The zeros of (x^2+7x+49)(x-7)=218 are

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^{2} + 7 x + 49) (x - 7) = 218

Solution steps

(x^{2} + 7 x + 49) (x - 7) = 218

Expand

(x^{2} + 7 x + 49) (x - 7) : x^{3} - 343

x^{3} - 343 = 218

Move

218

to the left side

x^{3} - 561 = 0

Factor

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

The solutions are

4 x^{3} - 2 x^{2} + 3 x - 1 = 0

x^{3} + 5 x^{2} - 14 x - 70 = 0

x^{3} + 3 x^{2} - 58 = 0

(x + 2)^{2} = x (x^{2} - 10 x + 25)

x^{4} - 11 x^{2} + 900 = 0

What are the solutions to the equation (x^2+7x+49)(x-7)=218 ?
The solutions to the equation (x^2+7x+49)(x-7)=218 are
Find the zeros of (x^2+7x+49)(x-7)=218
The zeros of (x^2+7x+49)(x-7)=218 are