What are the solutions to the equation 4x^3+5x+3=0 ?

The solutions to the equation 4x^3+5x+3=0 are x=-1/2 ,x= 1/4+i(sqrt(23))/4 ,x= 1/4-i(sqrt(23))/4

Find the zeros of 4x^3+5x+3=0

The zeros of 4x^3+5x+3=0 are x=-1/2 ,x= 1/4+i(sqrt(23))/4 ,x= 1/4-i(sqrt(23))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{3} + 5 x + 3 = 0

x = - \frac{1}{2}, x = \frac{1}{4} + i \frac{23}{4}, x = \frac{1}{4} - i \frac{23}{4}

Solution steps

4 x^{3} + 5 x + 3 = 0

Factor

4 x^{3} + 5 x + 3 : (2 x + 1) (2 x^{2} - x + 3)

(2 x + 1) (2 x^{2} - x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 1 = 0 or 2 x^{2} - x + 3 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

2 x^{2} - x + 3 = 0 : x = \frac{1}{4} + i \frac{23}{4}, x = \frac{1}{4} - i \frac{23}{4}

The solutions are

x = - \frac{1}{2}, x = \frac{1}{4} + i \frac{23}{4}, x = \frac{1}{4} - i \frac{23}{4}

z^{4} = - 0.25

r^{3} - r^{2} + r - 1 = 0

\frac{4 x ^{3} d - 1}{3} = 190

y, y = \frac{y ^{3}}{3}

x^{4} - 7 x + 12 = 0

What are the solutions to the equation 4x^3+5x+3=0 ?
The solutions to the equation 4x^3+5x+3=0 are x=-1/2 ,x= 1/4+i(sqrt(23))/4 ,x= 1/4-i(sqrt(23))/4
Find the zeros of 4x^3+5x+3=0
The zeros of 4x^3+5x+3=0 are x=-1/2 ,x= 1/4+i(sqrt(23))/4 ,x= 1/4-i(sqrt(23))/4