What is the answer to (x^2-x-22)^{4/3}=16 ?

The answer to (x^2-x-22)^{4/3}=16 is x=6,x=-5,x=(1+57^{1/2})/2 ,x=(1-57^{1/2})/2

Solve for x: (x^2-x-22)^{4/3}=16

The solution is x=6,x=-5,x=(1+57^{1/2})/2 ,x=(1-57^{1/2})/2

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(x^{2} - x - 22)^{\frac{4}{3}} = 16

x = 6, x = - 5, x = \frac{1 + 5 7 ^{\frac{1}{2}}}{2}, x = \frac{1 - 5 7 ^{\frac{1}{2}}}{2}

Decimal Notation

x = 6, x = - 5, x = 4.27491 \dots, x = - 3.27491 \dots

Solution steps

(x^{2} - x - 22)^{\frac{4}{3}} = 16

Take both sides of the equation to the power of

3 : (x^{2} - x - 22)^{4} = 4096

(x^{2} - x - 22)^{4} = 4096

Solve

(x^{2} - x - 22)^{4} = 4096 : x = 6, x = - 5, x = \frac{1 + 5 7 ^{\frac{1}{2}}}{2}, x = \frac{1 - 5 7 ^{\frac{1}{2}}}{2}

x = 6, x = - 5, x = \frac{1 + 5 7 ^{\frac{1}{2}}}{2}, x = \frac{1 - 5 7 ^{\frac{1}{2}}}{2}

Verify Solutions:

x = 6

True

, x = - 5

True

, x = \frac{1 + 5 7 ^{\frac{1}{2}}}{2}

True

, x = \frac{1 - 5 7 ^{\frac{1}{2}}}{2}

True

The solutions are

x = 6, x = - 5, x = \frac{1 + 5 7 ^{\frac{1}{2}}}{2}, x = \frac{1 - 5 7 ^{\frac{1}{2}}}{2}

3 x + 4 - x - 4 = 4

5 - x + 1 = x - 2

x = 8

x^{2} - x = 0

3 2 x - 3 + 2 7 - x = 11

What is the answer to (x^2-x-22)^{4/3}=16 ?
The answer to (x^2-x-22)^{4/3}=16 is x=6,x=-5,x=(1+57^{1/2})/2 ,x=(1-57^{1/2})/2
Solve for x: (x^2-x-22)^{4/3}=16
The solution is x=6,x=-5,x=(1+57^{1/2})/2 ,x=(1-57^{1/2})/2