What are the solutions to the equation x^2+12x+20=0 ?

The solutions to the equation x^2+12x+20=0 are x=-2,x=-10

Find the zeros of x^2+12x+20=0

The zeros of x^2+12x+20=0 are x=-2,x=-10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 12 x + 20 = 0

x = - 2, x = - 10

Solution steps

x^{2} + 12 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 20 = 8

x_{1, 2} = \frac{- 12 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 8}{2 \cdot 1}, x_{2} = \frac{- 12 - 8}{2 \cdot 1}

x = \frac{- 12 + 8}{2 \cdot 1} : - 2

x = \frac{- 12 - 8}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 2, x = - 10

- \frac{1}{2} (4)

(\frac{24}{25})^{2}

\frac{1}{8} - 2

x^{- 4}

5^{4} \cdot 5^{7}

What are the solutions to the equation x^2+12x+20=0 ?
The solutions to the equation x^2+12x+20=0 are x=-2,x=-10
Find the zeros of x^2+12x+20=0
The zeros of x^2+12x+20=0 are x=-2,x=-10