What is the answer to \sqrt[3]{2x+1}+8=0 ?

The answer to \sqrt[3]{2x+1}+8=0 is x=-513/2

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\sqrt[3]{2x+1}+8=0

x = - \frac{513}{2}

Decimal Notation

x = - 256.5

Solution steps

Move

8

to the right side

Take both sides of the equation to the power of

3 : 2 x + 1 = - 512

2 x + 1 = - 512

Solve

2 x + 1 = - 512 : x = - \frac{513}{2}

x = - \frac{513}{2}

Verify Solutions:

x = - \frac{513}{2}

True

The solution is

x = - \frac{513}{2}

x + 2 = x^{2} + 1

x^{\frac{2}{3}} = 9

x + 6 = x - 6

x = 1

x + 8 - x - 4 = 2

What is the answer to \sqrt[3]{2x+1}+8=0 ?
The answer to \sqrt[3]{2x+1}+8=0 is x=-513/2
Solve for x: \sqrt[3]{2x+1}+8=0
The solution is x=-513/2