What is the answer to sqrt(x^2-5x+4)+1-x=-3 ?

The answer to sqrt(x^2-5x+4)+1-x=-3 is x=4

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sqrt(x^2-5x+4)+1-x=-3

x^{2} - 5 x + 4 + 1 - x = - 3

x = 4

Solution steps

x^{2} - 5 x + 4 + 1 - x = - 3

Remove square roots

x^{2} - 5 x + 4 = x^{2} - 8 x + 16

Solve

x^{2} - 5 x + 4 = x^{2} - 8 x + 16 : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

x^{\frac{5}{3}} = 32

- 3 x - 2 = x + 2

2 x^{2} + 2 x - 3 x^{2} + x + 3 = 3

y, x = 4 - y^{2}

y (y - 15) - 4 = 0

What is the answer to sqrt(x^2-5x+4)+1-x=-3 ?
The answer to sqrt(x^2-5x+4)+1-x=-3 is x=4
Solve for x: sqrt(x^2-5x+4)+1-x=-3
The solution is x=4