What is the answer to solvefor x,ysqrt(5-2x)-3=0 ?

The answer to solvefor x,ysqrt(5-2x)-3=0 is x=-(9-5y^2)/(2y^2) {y 0}

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solvefor x,ysqrt(5-2x)-3=0

solve for

x, y 5 - 2 x - 3 = 0

x = - \frac{9 - 5 y ^{2}}{2 y ^{2}} {y < 0 or y > 0}

Solution steps

y 5 - 2 x - 3 = 0

Move

3

to the right side

y 5 - 2 x = 3

Divide both sides by

y

5 - 2 x = \frac{3}{y}

Square both sides:

5 - 2 x = \frac{9}{y ^{2}}

5 - 2 x = \frac{9}{y ^{2}}

Solve

5 - 2 x = \frac{9}{y ^{2}} : x = - \frac{9 - 5 y ^{2}}{2 y ^{2}}

x = - \frac{9 - 5 y ^{2}}{2 y ^{2}}

Verify Solutions:

x = - \frac{9 - 5 y ^{2}}{2 y ^{2}} {y < 0 or y > 0}

The solution is

x = - \frac{9 - 5 y ^{2}}{2 y ^{2}} {y < 0 or y > 0}

8 - 2 x - x = 0

- x = 2 - (10 x - 5)

3 x + 4 - 2 = 2 x - 4

x^{\frac{1}{3}} = 3

x - 1 = 0

What is the answer to solvefor x,ysqrt(5-2x)-3=0 ?
The answer to solvefor x,ysqrt(5-2x)-3=0 is x=-(9-5y^2)/(2y^2) {y<0\lor y>0}