What is the answer to 2+(sqrt(x^2-9))/(x-4)=0 ?

The answer to 2+(sqrt(x^2-9))/(x-4)=0 is x=(16-sqrt(37))/3

Solve for x: 2+(sqrt(x^2-9))/(x-4)=0

The solution is x=(16-sqrt(37))/3

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2 + \frac{x ^{2} - 9}{x - 4} = 0

x = \frac{16 - 37}{3}

Decimal Notation

x = 3.30574 \dots

Solution steps

2 + \frac{x ^{2} - 9}{x - 4} = 0

Multiply both sides by

x - 4

2 (x - 4) + \frac{x ^{2} - 9}{x - 4} (x - 4) = 0 \cdot (x - 4)

Simplify

2 (x - 4) + x^{2} - 9 = 0

Expand

2 (x - 4) + x^{2} - 9 : 2 x - 8 + x^{2} - 9

2 x - 8 + x^{2} - 9 = 0

Remove square roots

x^{2} - 9 = 4 x^{2} - 32 x + 64

Solve

x^{2} - 9 = 4 x^{2} - 32 x + 64 : x = \frac{16 + 37}{3}, x = \frac{16 - 37}{3}

x = \frac{16 + 37}{3}, x = \frac{16 - 37}{3}

Verify Solutions:

x = \frac{16 + 37}{3}

False

, x = \frac{16 - 37}{3}

True

The solution is

x = \frac{16 - 37}{3}

2 x + 7 - x = 2

x + 6 = x + 4

x^{\frac{3}{2}} = x^{3}

4 y + 1 - y - 2 = 3

What is the answer to 2+(sqrt(x^2-9))/(x-4)=0 ?
The answer to 2+(sqrt(x^2-9))/(x-4)=0 is x=(16-sqrt(37))/3
Solve for x: 2+(sqrt(x^2-9))/(x-4)=0
The solution is x=(16-sqrt(37))/3