What is the answer to sqrt(2x-7)=sqrt(x)+1 ?

The answer to sqrt(2x-7)=sqrt(x)+1 is x=16

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sqrt(2x-7)=sqrt(x)+1

2 x - 7 = x + 1

x = 16

Solution steps

2 x - 7 = x + 1

Remove square roots

x^{2} - 16 x + 64 = 4 x

Solve

x^{2} - 16 x + 64 = 4 x : x = 16, x = 4

x = 16, x = 4

Verify Solutions:

x = 16

True

, x = 4

False

The solution is

x = 16

x = 3 + 24 - 4 x

x = - 2

2 x + 2 - x + 2 = - 1

3 x + 8 = 4 x + 1

(x + 1)^{\frac{2}{3}} = 4

What is the answer to sqrt(2x-7)=sqrt(x)+1 ?
The answer to sqrt(2x-7)=sqrt(x)+1 is x=16
Solve for x: sqrt(2x-7)=sqrt(x)+1
The solution is x=16