What is the answer to \sqrt[3]{x^2-x+6}-2=0 ?

The answer to \sqrt[3]{x^2-x+6}-2=0 is x=2,x=-1

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\sqrt[3]{x^2-x+6}-2=0

x = 2, x = - 1

Solution steps

Move

2

to the right side

Take both sides of the equation to the power of

3 : x^{2} - x + 6 = 8

x^{2} - x + 6 = 8

Solve

x^{2} - x + 6 = 8 : x = 2, x = - 1

x = 2, x = - 1

Verify Solutions:

x = 2

True

, x = - 1

True

The solutions are

x = 2, x = - 1

x - 3 x - 18 = 0

2 x - 3 - x + 7 + 2 = 0

4 x - 6 = x

x = 2 2 x - 4

x - 4 x + 3 = 0

What is the answer to \sqrt[3]{x^2-x+6}-2=0 ?
The answer to \sqrt[3]{x^2-x+6}-2=0 is x=2,x=-1
Solve for x: \sqrt[3]{x^2-x+6}-2=0
The solution is x=2,x=-1