What are the solutions to the equation 132=x^2+9x+20 ?

The solutions to the equation 132=x^2+9x+20 are x=7,x=-16

Find the zeros of 132=x^2+9x+20

The zeros of 132=x^2+9x+20 are x=7,x=-16

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132 = x^{2} + 9 x + 20

x = 7, x = - 16

Solution steps

132 = x^{2} + 9 x + 20

Switch sides

x^{2} + 9 x + 20 = 132

Move

132

to the left side

x^{2} + 9 x - 112 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 112 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 112) = 23

x_{1, 2} = \frac{- 9 \pm 23}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 23}{2 \cdot 1}, x_{2} = \frac{- 9 - 23}{2 \cdot 1}

x = \frac{- 9 + 23}{2 \cdot 1} : 7

x = \frac{- 9 - 23}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = 7, x = - 16

- h^{2} + 6 h \geq 13000

\frac{5 !}{2 !}

w x^{2} y - 9 w x y + 14 w y

3 x^{2} - 20 x + 25

3 x = 10 - 2 x

What are the solutions to the equation 132=x^2+9x+20 ?
The solutions to the equation 132=x^2+9x+20 are x=7,x=-16
Find the zeros of 132=x^2+9x+20
The zeros of 132=x^2+9x+20 are x=7,x=-16