What is the answer to z+2=sqrt(2z^2+3z+7)-3 ?

The answer to z+2=sqrt(2z^2+3z+7)-3 is z=-2,z=9

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z+2=sqrt(2z^2+3z+7)-3

z + 2 = 2 z^{2} + 3 z + 7 - 3

z = - 2, z = 9

Solution steps

z + 2 = 2 z^{2} + 3 z + 7 - 3

Remove square roots

z^{2} + 10 z + 25 = 2 z^{2} + 3 z + 7

Solve

z^{2} + 10 z + 25 = 2 z^{2} + 3 z + 7 : z = - 2, z = 9

z = - 2, z = 9

Verify Solutions:

z = - 2

True

, z = 9

True

The solutions are

z = - 2, z = 9

x, y = x

x + 7 x^{\frac{1}{2}} - 18 = 0

3 x + 1 = x + 1

2 x - 1 = 3 x - 5

z = 9 z - 20

What is the answer to z+2=sqrt(2z^2+3z+7)-3 ?
The answer to z+2=sqrt(2z^2+3z+7)-3 is z=-2,z=9
Solve for z: z+2=sqrt(2z^2+3z+7)-3
The solution is z=-2,z=9