What is the answer to \sqrt[3]{x^2-8}=2 ?

The answer to \sqrt[3]{x^2-8}=2 is x=4,x=-4

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\sqrt[3]{x^2-8}=2

x = 4, x = - 4

Solution steps

Take both sides of the equation to the power of

3 : x^{2} - 8 = 8

x^{2} - 8 = 8

Solve

x^{2} - 8 = 8 : x = 4, x = - 4

x = 4, x = - 4

Verify Solutions:

x = 4

True

, x = - 4

True

The solutions are

x = 4, x = - 4

2 x + 28 = x + 4

2 x^{2} - 5 x + 7 = 0

2 x + 2 - x + 8 = 1

x - 4 = 4

x + 5 - 2 x = 3

What is the answer to \sqrt[3]{x^2-8}=2 ?
The answer to \sqrt[3]{x^2-8}=2 is x=4,x=-4
Solve for x: \sqrt[3]{x^2-8}=2
The solution is x=4,x=-4