What are the solutions to the equation 2(x-3)-3x(x-4)=10 ?

The solutions to the equation 2(x-3)-3x(x-4)=10 are x=2,x= 8/3

Find the zeros of 2(x-3)-3x(x-4)=10

The zeros of 2(x-3)-3x(x-4)=10 are x=2,x= 8/3

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2 (x - 3) - 3 x (x - 4) = 10

x = 2, x = \frac{8}{3}

Solution steps

2 (x - 3) - 3 x (x - 4) = 10

Expand

2 (x - 3) - 3 x (x - 4) : - 3 x^{2} + 14 x - 6

- 3 x^{2} + 14 x - 6 = 10

Move

10

to the left side

- 3 x^{2} + 14 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 ( - 3 ) ( - 16 )}{2 ( - 3 )}

1 4^{2} - 4 (- 3) (- 16) = 2

x_{1, 2} = \frac{- 14 \pm 2}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 14 + 2}{2 ( - 3 )}, x_{2} = \frac{- 14 - 2}{2 ( - 3 )}

x = \frac{- 14 + 2}{2 ( - 3 )} : 2

x = \frac{- 14 - 2}{2 ( - 3 )} : \frac{8}{3}

The solutions to the quadratic equation are:

x = 2, x = \frac{8}{3}

5 (x - 2) + 3 x - 4 = - 38

∣ 5 x ∣ = 1

3 x + 6 = 5 x + 18

9 x^{2} - 64

5 ∣ x + 4 ∣ \leq 10

What are the solutions to the equation 2(x-3)-3x(x-4)=10 ?
The solutions to the equation 2(x-3)-3x(x-4)=10 are x=2,x= 8/3
Find the zeros of 2(x-3)-3x(x-4)=10
The zeros of 2(x-3)-3x(x-4)=10 are x=2,x= 8/3