What is the answer to sqrt((2-y)^2)=y-2 ?

The answer to sqrt((2-y)^2)=y-2 is y>= 2

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sqrt((2-y)^2)=y-2

(2 - y)^{2} = y - 2

y \geq 2

Solution steps

(2 - y)^{2} = y - 2

Square both sides:

(2 - y)^{2} = y^{2} - 4 y + 4

(2 - y)^{2} = y^{2} - 4 y + 4

Solve

(2 - y)^{2} = y^{2} - 4 y + 4 :

True for all

y

True for all y

Verify Solutions:

y < 2

False

, y = 2

True

, y > 2

True

The solution is

y \geq 2

(x + 6)^{\frac{1}{2}} = 7

x - 15 - 2 x = 0

(3 x - 2) + x - 1 - 3 = 0

x = 2 3 x - 9

x - 2 = 0

What is the answer to sqrt((2-y)^2)=y-2 ?
The answer to sqrt((2-y)^2)=y-2 is y>= 2
Solve for y: sqrt((2-y)^2)=y-2
The solution is y>= 2