What are the solutions to the equation 3x^2-12x-7=0 ?

The solutions to the equation 3x^2-12x-7=0 are x=(6+sqrt(57))/3 ,x=(6-sqrt(57))/3

Find the zeros of 3x^2-12x-7=0

The zeros of 3x^2-12x-7=0 are x=(6+sqrt(57))/3 ,x=(6-sqrt(57))/3

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3 x^{2} - 12 x - 7 = 0

x = \frac{6 + 57}{3}, x = \frac{6 - 57}{3}

Solution steps

3 x^{2} - 12 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 (- 7) = 257

x_{1, 2} = \frac{- ( - 12 ) \pm 2 57}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 57}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 2 57}{2 \cdot 3}

x = \frac{- ( - 12 ) + 2 57}{2 \cdot 3} : \frac{6 + 57}{3}

x = \frac{- ( - 12 ) - 2 57}{2 \cdot 3} : \frac{6 - 57}{3}

The solutions to the quadratic equation are:

x = \frac{6 + 57}{3}, x = \frac{6 - 57}{3}

(n + 2) (n - 2) = 0

5 x^{2} - 3 x

12 c^{2} + 60 c + 75

\frac{4 + 10 i}{3 + i}

a^{2} - 14 ab + 48 b^{2}

What are the solutions to the equation 3x^2-12x-7=0 ?
The solutions to the equation 3x^2-12x-7=0 are x=(6+sqrt(57))/3 ,x=(6-sqrt(57))/3
Find the zeros of 3x^2-12x-7=0
The zeros of 3x^2-12x-7=0 are x=(6+sqrt(57))/3 ,x=(6-sqrt(57))/3