What is the answer to x^2-4=\sqrt[3]{2x} ?

The answer to x^2-4=\sqrt[3]{2x} is x\approx-1.59039…,x\approx 2.38392…

Solve for x: x^2-4=\sqrt[3]{2x}

The solution is x\approx-1.59039…,x\approx 2.38392…

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x \approx - 1.59039 \dots, x \approx 2.38392 \dots

Solution steps

Take both sides of the equation to the power of

3 : x^{6} - 12 x^{4} + 48 x^{2} - 64 = 2 x

x^{6} - 12 x^{4} + 48 x^{2} - 64 = 2 x

Solve

x^{6} - 12 x^{4} + 48 x^{2} - 64 = 2 x : x \approx - 1.59039 \dots, x \approx 2.38392 \dots

x \approx - 1.59039 \dots, x \approx 2.38392 \dots

Verify Solutions:

x \approx - 1.59039 \dots

True

, x \approx 2.38392 \dots

True

The solutions are

x \approx - 1.59039 \dots, x \approx 2.38392 \dots

1 = y^{2}

3 x - 1 - 2 = 0

x, x + y = 10

x + 2 = 2 x - 5

x + 3 = 4

What is the answer to x^2-4=\sqrt[3]{2x} ?
The answer to x^2-4=\sqrt[3]{2x} is x\approx-1.59039…,x\approx 2.38392…
Solve for x: x^2-4=\sqrt[3]{2x}
The solution is x\approx-1.59039…,x\approx 2.38392…