What is the answer to 2x^2-11x+21=3\sqrt[3]{4x-4} ?

The answer to 2x^2-11x+21=3\sqrt[3]{4x-4} is x=3

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2x^2-11x+21=3\sqrt[3]{4x-4}

x = 3

Solution steps

Take both sides of the equation to the power of

3 : 8 x^{6} - 132 x^{5} + 978 x^{4} - 4103 x^{3} + 10269 x^{2} - 14553 x + 9261 = 108 x - 108

8 x^{6} - 132 x^{5} + 978 x^{4} - 4103 x^{3} + 10269 x^{2} - 14553 x + 9261 = 108 x - 108

Solve

8 x^{6} - 132 x^{5} + 978 x^{4} - 4103 x^{3} + 10269 x^{2} - 14553 x + 9261 = 108 x - 108 : x = 3

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

x - 1 + x + 2 = 3

(x - 1)^{\frac{2}{3}} - 25 = 0

- 4 x + 12 = x

What is the answer to 2x^2-11x+21=3\sqrt[3]{4x-4} ?
The answer to 2x^2-11x+21=3\sqrt[3]{4x-4} is x=3
Solve for x: 2x^2-11x+21=3\sqrt[3]{4x-4}
The solution is x=3