What are the solutions to the equation -9=x^2+6x ?

The solutions to the equation -9=x^2+6x are x=-3

Find the zeros of -9=x^2+6x

The zeros of -9=x^2+6x are x=-3

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- 9 = x^{2} + 6 x

x = - 3

Solution steps

- 9 = x^{2} + 6 x

Switch sides

x^{2} + 6 x = - 9

Move

9

to the left side

x^{2} + 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

x = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

x = - 3

The solution to the quadratic equation is:

x = - 3

2 x = 17

\frac{\frac{14}{( x + h ) ^{2}} - \frac{14}{x ^{2}}}{h}

6 x - 8 = 4 x

- 3 (4 r - 8) = - 36

\frac{1}{2 ^{5}}

What are the solutions to the equation -9=x^2+6x ?
The solutions to the equation -9=x^2+6x are x=-3
Find the zeros of -9=x^2+6x
The zeros of -9=x^2+6x are x=-3