What is the answer to sqrt(r+1)+sqrt(4r-3)=5 ?

The answer to sqrt(r+1)+sqrt(4r-3)=5 is r=3

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sqrt(r+1)+sqrt(4r-3)=5

r + 1 + 4 r - 3 = 5

r = 3

Solution steps

r + 1 + 4 r - 3 = 5

Remove square roots

9 r^{2} + 126 r + 441 = 400 r - 300

Solve

9 r^{2} + 126 r + 441 = 400 r - 300 : r = \frac{247}{9}, r = 3

r = \frac{247}{9}, r = 3

Verify Solutions:

r = \frac{247}{9}

False

, r = 3

True

The solution is

r = 3

x + 6 - 2 = x - 2

x = 7 x

2 x - 3 + x + 7 = 4

x^{0.6} (x - 1) = 9 (x + 2)

7 x - 3 = 5

What is the answer to sqrt(r+1)+sqrt(4r-3)=5 ?
The answer to sqrt(r+1)+sqrt(4r-3)=5 is r=3
Solve for r: sqrt(r+1)+sqrt(4r-3)=5
The solution is r=3