What is the answer to 2x+sqrt(x^2+x-1)=3 ?

The answer to 2x+sqrt(x^2+x-1)=3 is x=1

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2x+sqrt(x^2+x-1)=3

2 x + x^{2} + x - 1 = 3

x = 1

Solution steps

2 x + x^{2} + x - 1 = 3

Remove square roots

x^{2} + x - 1 = 9 - 12 x + 4 x^{2}

Solve

x^{2} + x - 1 = 9 - 12 x + 4 x^{2} : x = 1, x = \frac{10}{3}

x = 1, x = \frac{10}{3}

Verify Solutions:

x = 1

True

, x = \frac{10}{3}

False

The solution is

x = 1

d, t = 5 fd - H

3 + 2 z = 3 z + 21 - 2 z

x^{3} = x + 4

n (x - 3) = x - 3

2 x - 5 - x - 2 = 2

What is the answer to 2x+sqrt(x^2+x-1)=3 ?
The answer to 2x+sqrt(x^2+x-1)=3 is x=1
Solve for x: 2x+sqrt(x^2+x-1)=3
The solution is x=1